E operator &(E x, E y); E operator |(E x, E y); E operator ^(E x, E y);Paragraph 21 The result of evaluating x op y, where x and y are expressions of an enumeration type E with an underlying type U, and op is one of the logical operators, is exactly the same as evaluating (E)((U)x op (U)y). 2 In other words, the enumeration type logical operators simply perform the logical operation on the underlying type of the two operands.

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