Jon Jagger
Table of Contents 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Notes DownloadECMA-334 C# Language Specificationpreviousnextprevious at this levelnext at this level 11 Typesprevious at this levelnext at this level 11.1 Value typesprevious at this levelnext at this level 11.1.5 Floating point types Paragraph 11 C# supports two floating-point types: float and double. 2 The float and double types are represented using the 32-bit single-precision and 64-bit double-precision IEEE 754 formats, which provide the following sets of values: Paragraph 21 The float type can represent values ranging from approximately 1.5 × 10-45 to 3.4 × 1038 with a precision of 7 digits. Paragraph 31 The double type can represent values ranging from approximately 5.0 × 10-324 to 1.7 × 10308 with a precision of 15-16 digits. Paragraph 41 If one of the operands of a binary operator is of a floating-point type, then the other operand must be of an integral type or a floating-point type, and the operation is evaluated as follows: Paragraph 51 The floating-point operators, including the assignment operators, never produce exceptions. 2 Instead, in exceptional situations, floating-point operations produce zero, infinity, or NaN, as described below: Paragraph 61 Floating-point operations may be performed with higher precision than the result type of the operation. [Example: For example, some hardware architectures support an "extended" or "long double" floating-point type with greater range and precision than the double type, and implicitly perform all floating-point operations using this higher precision type. Only at excessive cost in performance can such hardware architectures be made to perform floating-point operations with less precision, and rather than require an implementation to forfeit both performance and precision, C# allows a higher precision type to be used for all floating-point operations. Other than delivering more precise results, this rarely has any measurable effects. However, in expressions of the form x * y / z, where the multiplication produces a result that is outside the double range, but the subsequent division brings the temporary result back into the double range, the fact that the expression is evaluated in a higher range format may cause a finite result to be produced instead of an infinity. end example]
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